Calculus...........d/dx[ln(e^i)]...

Point to remember..

d/dx(constant)=0


Now,

d/dx[ln(e^i)]

= d/dx[i.ln.(e)]

'i' and ln(e) both has numerical values


So,


d/dx[i.ln.(e)]

=0

ln(e^i) is a constant, and the derivative of a constant is zero.

d/dx[ln(e^i)] = d/dx[i*lne] = d/dx[i] = 0 >===========< ANSWER

0