Could you please show your work
1) For a normal distribution with a mean of 30 and a standard deviation of 5, the probability of getting a value less than 20 or greater tahn 35 is
2)On a recent test, scores of 54 and 64 corresponded to z-scores of -1.0 and 1.5 respectively. Find the class mean and average.
3)the marks of 1200 students who wrote a Math diploma exam are normally distributed. The diagram below indicates 169 students had a mark above a particular z-score. The z-score is
4)Determine the mean and standard deviation for each set of sport data
a. 72,74,73,76,74,71,75,76,72,77
b.(100m dash (sec)) 10.8,10.6,10.8,9.9,10.2,10.3,10.4,10
1) For a normal distribution with a mean of 30 and a standard deviation of 5, the probability of getting a value less than 20 or greater tahn 35 is
2)On a recent test, scores of 54 and 64 corresponded to z-scores of -1.0 and 1.5 respectively. Find the class mean and average.
3)the marks of 1200 students who wrote a Math diploma exam are normally distributed. The diagram below indicates 169 students had a mark above a particular z-score. The z-score is
4)Determine the mean and standard deviation for each set of sport data
a. 72,74,73,76,74,71,75,76,72,77
b.(100m dash (sec)) 10.8,10.6,10.8,9.9,10.2,10.3,10.4,10
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Use the formula z=(X-饾泹)/饾潏
1) z=(X-饾泹)/饾潏=(35-30)/5=5/5=1
P(X>35)=P(z>1)=1-P(z<1)=1-0.8413=0.158鈥?br>
2) z=(X-饾泹)/饾潏
-1=(54-饾泹)/饾潏
-饾潏=54-饾泹 or 饾泹-饾潏 =54 ..(1)
1.5=(64-饾泹)/饾潏
1.5饾潏=64-饾泹 or 饾泹+1.5饾潏=64 ...(2)
Solve the system by multiplying (1) by -1 and adding them
饾泹-饾潏 =54 ..(1)
饾泹+1.5饾潏=64 ...(2)
-----------------
2.5饾潏=10
饾潏=10/2.5= 4
Substitute 饾潏 in (1)
饾泹-4 =54 then 饾泹=58
I think you meant the mean and standard deviation not the mean and average.
3)There is no diagram
But I can guess
1200-169=1031
Find proportion of those who got less than z is
1031/1200=0.8592 this is the area under z so call it a
P(z
4) Use a calculator or the formulas for mean and SD
a) mean=74 SD=2
b) mean=10.4 SD=0.24
1) z=(X-饾泹)/饾潏=(35-30)/5=5/5=1
P(X>35)=P(z>1)=1-P(z<1)=1-0.8413=0.158鈥?br>
2) z=(X-饾泹)/饾潏
-1=(54-饾泹)/饾潏
-饾潏=54-饾泹 or 饾泹-饾潏 =54 ..(1)
1.5=(64-饾泹)/饾潏
1.5饾潏=64-饾泹 or 饾泹+1.5饾潏=64 ...(2)
Solve the system by multiplying (1) by -1 and adding them
饾泹-饾潏 =54 ..(1)
饾泹+1.5饾潏=64 ...(2)
-----------------
2.5饾潏=10
饾潏=10/2.5= 4
Substitute 饾潏 in (1)
饾泹-4 =54 then 饾泹=58
I think you meant the mean and standard deviation not the mean and average.
3)There is no diagram
But I can guess
1200-169=1031
Find proportion of those who got less than z is
1031/1200=0.8592 this is the area under z so call it a
P(z
4) Use a calculator or the formulas for mean and SD
a) mean=74 SD=2
b) mean=10.4 SD=0.24