Express using only positive exponents.
(2a^2b^-3 / 3bc^-4)
The answer is (2a^2c^4 / 3b^4), but can someone show me the steps. Thanks!
(2a^2b^-3 / 3bc^-4)
The answer is (2a^2c^4 / 3b^4), but can someone show me the steps. Thanks!
-
(2a^2b^-3 / 3bc^-4)
Remember that a negative exponent means reciprocal.
So x^-n = 1/(x^n)
And 1/(x^-n) = (x^n)
Using this fact (and typing the fraction a little differently so it's easier to see), you go from:
2(a^2)(b^-3)
-----------------
3(b)(c^-4)
to
2(a^2)(c^4)
---------------
3(b)(b^3)
Collecting the b's
2(a^2)(c^4)
---------------
3(b^4)
Remember that a negative exponent means reciprocal.
So x^-n = 1/(x^n)
And 1/(x^-n) = (x^n)
Using this fact (and typing the fraction a little differently so it's easier to see), you go from:
2(a^2)(b^-3)
-----------------
3(b)(c^-4)
to
2(a^2)(c^4)
---------------
3(b)(b^3)
Collecting the b's
2(a^2)(c^4)
---------------
3(b^4)
-
Negative exponents = invert
... ( 2a^(2) b^(-3) ) ÷ ( 3 b c^(-4) )
or ( 2a^(2) / b^(3) ) ÷ ( 3 b / c^(4) )
or ( 2a^(2) / b^(3) ) * ( c^(4) / 3 b)
or ( 2a^(2) * c^(4) ) / ( b^(3) * 3 b)
or ( 2 a^(2) * c^(4) ) / ( 3 b^(4) )
... ( 2a^(2) b^(-3) ) ÷ ( 3 b c^(-4) )
or ( 2a^(2) / b^(3) ) ÷ ( 3 b / c^(4) )
or ( 2a^(2) / b^(3) ) * ( c^(4) / 3 b)
or ( 2a^(2) * c^(4) ) / ( b^(3) * 3 b)
or ( 2 a^(2) * c^(4) ) / ( 3 b^(4) )
-
yea man, you know the r00lz of exponent stuff? then its ez..
First of all b^-3 = 1/b^3 and 1/c^-4 = c^4:
If thats cleared.. Then answers will also be clear, yea?
First of all b^-3 = 1/b^3 and 1/c^-4 = c^4:
If thats cleared.. Then answers will also be clear, yea?
-
2a^2b^-3 is not clear
-
Nope, never had to