Help please!! Math!! 1 Question! 10 points!
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Help please!! Math!! 1 Question! 10 points!

[From: ] [author: ] [Date: 11-12-23] [Hit: ]
...or( 2 a^(2) * c^(4) )/ ( 3 b^(4) )-yea man, you know the r00lz of exponent stuff? then its ez.......
Express using only positive exponents.

(2a^2b^-3 / 3bc^-4)


The answer is (2a^2c^4 / 3b^4), but can someone show me the steps. Thanks!

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(2a^2b^-3 / 3bc^-4)

Remember that a negative exponent means reciprocal.

So x^-n = 1/(x^n)
And 1/(x^-n) = (x^n)

Using this fact (and typing the fraction a little differently so it's easier to see), you go from:

2(a^2)(b^-3)
-----------------
3(b)(c^-4)

to

2(a^2)(c^4)
---------------
3(b)(b^3)

Collecting the b's

2(a^2)(c^4)
---------------
3(b^4)

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Negative exponents = invert

... ( 2a^(2) b^(-3) ) ÷ ( 3 b c^(-4) )
or ( 2a^(2) / b^(3) ) ÷ ( 3 b / c^(4) )
or ( 2a^(2) / b^(3) ) * ( c^(4) / 3 b)
or ( 2a^(2) * c^(4) ) / ( b^(3) * 3 b)
or ( 2 a^(2) * c^(4) ) / ( 3 b^(4) )

-
yea man, you know the r00lz of exponent stuff? then its ez..

First of all b^-3 = 1/b^3 and 1/c^-4 = c^4:

If thats cleared.. Then answers will also be clear, yea?

-
2a^2b^-3 is not clear

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Nope, never had to
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