How do i solve the equation by using the quadratic formula

please help me
solve the equation by using the quadratic formula X^2-3x=10
thank you in advance.

x^2 - 3x = 10

subtract the 10

x^2 - 3x - 10 = 0

the quadratic formula is:

x = -b +/- sqrt (b^2 - 4ac)
......___________________
..............2a

where the equation we want to solve is ax^2 + bx + c = 0

so here: a=1, b= -3 and c = -10

x = 3 +/- sqrt ( (-3)^2 - 4 * 1 * -10)
____________________________
.................2 * 1


x = 3 + /- sqrt (9 + 40)
......________________
...........2

x = 3 +/ - 7
__________

......2


so x = 3 + 7 = 10 /2 = 5

or

x = 3 - 7 = -4 / 2 = -2.

X^2-3x=10
Subtract 10 from both sides
X^2-3x-10
Now you have your a,b, and c for the formula.
A=1
B=-3
C=-10
The Quadratic formula is:
-b plus or minus the square root of [b^2-(4ac)] and then all of that over 2a.
You should have two answers because you subtract the square root quantity in one, and add it the next time you work out the problem.

x^2 - 3x = 10

Subtract 10 from each side:

x^2 - 3x - 10 = 0

There you have the standard form to use with your formula,
a = 1,
b = -3,
c = -10