Hey, I am having some issues solving this problem! Can someone please help me?
2Al+3H2SO4--------->Al2(SO4)3+3H2
They want the net ionic equation, everything is Aq except the Hydrogen which is gas.
2Al+3H2SO4--------->Al2(SO4)3+3H2
They want the net ionic equation, everything is Aq except the Hydrogen which is gas.
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2Al + 3H2SO4 ---> Al2(SO4)3 + 3H2 ===>
2Al + 6H(1+) + 3SO4(2-) ---> 2Al(3+) +3SO4(2-) +3H2 ===>
2Al + 6H(1+) ---> 2Al(3+) + 3H2
H2SO4 dissociates in aqueous solution to 2H(1+) + SO4(2-)
Al2(SO4)3 dissociates to Al(3+) + 3SO4(2-)
Since the SO4(2-) remains unchanged on both sides of the equation it can be subtracted out from both sides, giving the net equation.
2Al + 6H(1+) + 3SO4(2-) ---> 2Al(3+) +3SO4(2-) +3H2 ===>
2Al + 6H(1+) ---> 2Al(3+) + 3H2
H2SO4 dissociates in aqueous solution to 2H(1+) + SO4(2-)
Al2(SO4)3 dissociates to Al(3+) + 3SO4(2-)
Since the SO4(2-) remains unchanged on both sides of the equation it can be subtracted out from both sides, giving the net equation.