For this problem: a experiment began with 200 of a certain type of bacteria. The bacteria grew exponetially and 4 hours later there were 18000.
What would my equation be for this problem? Y=200(90)^x?
What would my equation be for this problem? Y=200(90)^x?
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If I let t represent time in hours. It took it 4 hours to have a population 90 times so t/4.
y=A(90)^(t/4). If I take t=0, I find y=A, which is the starting population.
y=200(90)^(t/4)
y=A(90)^(t/4). If I take t=0, I find y=A, which is the starting population.
y=200(90)^(t/4)
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no, there's a growth factor, g, such that
18,000 = 200g^4
and solving for g,
90 = g^4
g = 3.08007
18,000 = 200g^4
and solving for g,
90 = g^4
g = 3.08007