need to show the work plz. thanks:)
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You can't solve for x and y because you have two unknowns and only one equation.
In terms of x it can be rewritten
x=-3/2y+5 divide your equation by 2
Or for y can be written as
2x=-3y+10
3y+2x=10 (adding 3y to each side)
3y=-2x+10 (taking away 2x on each side)
y=-2/3x+10/3 (dividing by 3 on wax side)
In terms of x it can be rewritten
x=-3/2y+5 divide your equation by 2
Or for y can be written as
2x=-3y+10
3y+2x=10 (adding 3y to each side)
3y=-2x+10 (taking away 2x on each side)
y=-2/3x+10/3 (dividing by 3 on wax side)
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Since there are an infinite number of real solutions, I will concentrate on showing how to find positive integral solutions.
2x = 10 - 3y
x = 5 - y - y/2
Let t = y/2
(A) so x = 5 - y - t
then if t = y/2, y = 2t
Substitute y back into the equation at (A)
x = 5 - 2t - t = 5 - 3t
so now we have
y = 2t, and x = 5 - 3t
for positive integral solutions, x and y must be > 0 so
2t > 0 then t > 0
5 - 3t > 0
-3t > -5
t < 5/3, t <= 1
Since t is constrained to be an integer greater than 0 or less than or equal to 1, there is only one solution (when t = 1) Note: If you want any integral solution, the just chose any integral value of t.
Check:
Let t = 1
y = 2, x = 2
for 2x = 10 - 3y, 4 = 10-6 = 4
Jim
2x = 10 - 3y
x = 5 - y - y/2
Let t = y/2
(A) so x = 5 - y - t
then if t = y/2, y = 2t
Substitute y back into the equation at (A)
x = 5 - 2t - t = 5 - 3t
so now we have
y = 2t, and x = 5 - 3t
for positive integral solutions, x and y must be > 0 so
2t > 0 then t > 0
5 - 3t > 0
-3t > -5
t < 5/3, t <= 1
Since t is constrained to be an integer greater than 0 or less than or equal to 1, there is only one solution (when t = 1) Note: If you want any integral solution, the just chose any integral value of t.
Check:
Let t = 1
y = 2, x = 2
for 2x = 10 - 3y, 4 = 10-6 = 4
Jim
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There are more variables, 2, than equations, 1, so there are infinitely many solutions.
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LOL:) ok.........
2X=-3y+10
» 2x+3y=10
»let x=0
»2(0)+3y=10
»3y=10
»y=3.33
»(0,3.33)
»let y=0
»2x+3(0)=10
»2x=10
»x=5
»(5,0)
Hope i helped :)
2X=-3y+10
» 2x+3y=10
»let x=0
»2(0)+3y=10
»3y=10
»y=3.33
»(0,3.33)
»let y=0
»2x+3(0)=10
»2x=10
»x=5
»(5,0)
Hope i helped :)
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Its not possible to solve...
Unless you want to solve for x or y...
I suggest you rephrase your question
Unless you want to solve for x or y...
I suggest you rephrase your question