1,2,4,8,16,32,64,128 ?
What I have as a conjecture is "The sum of the elements in the nth row is 2^n (2 to the nth power)."
I'd really appreciate your help! Thanks!
What I have as a conjecture is "The sum of the elements in the nth row is 2^n (2 to the nth power)."
I'd really appreciate your help! Thanks!
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The successive numbers in the nth row of the Pascal's triangle are the terms in the binomial expansion of (1+1)^n. That is why the sum is 2^n.
The sequence that you have provided is a GP with common ratio r = 2.
It is not understood as to what has to be proved here.
The sequence that you have provided is a GP with common ratio r = 2.
It is not understood as to what has to be proved here.