A fair coin is tossed 3 times....
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A fair coin is tossed 3 times....

[From: ] [author: ] [Date: 11-12-12] [Hit: ]
1, 2, 3 heads P( A or (not B)) = 1For P((not A) or B or (not C)) not A = 0 headB = 2, 3 headsnot C = 0,......

= P(0 heads) + P(2 heads) + P(3 heads) note: Notice that this is is basically the probability that we WILL NOT have 1 head, so it can all be replaced with P(not 1 head).

= P(not 1 head)

= 1 - P(1 head) note: Notice that P(not 1 head) is the same as 1 - P(1 head) or 100% - P(1 head).

= 1 - [(1/2)(1/2)(1/2) + (1/2)(1/2)(1/2) + (1/2)(1/2)(1/2)]

= 1 - [3/8] note: I skipped steps since we calculated P(1 head) in part (a).

= 5/8

If you need any more help, please ask.

-
the tossed are: (8 outcomes)
hhh
hht
hth
htt
thh
tht
tth
ttt
P(C) = P(head 1 or 3) = 4/8

not B is : 0 head or 1 head only so A or (not B) or 0, 1, 2, 3 heads
P( A or (not B)) = 1

For P((not A) or B or (not C))

not A = 0 head
B = 2, 3 heads
not C = 0, 2 so 1 head is missing or 3 combinations

p((not A) or B or (not C)) = 1 - 3/8 = 5/8
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