Please explain how to answer this AS Mechanics
Favorites|Homepage
Subscriptions | sitemap
HOME > > Please explain how to answer this AS Mechanics

Please explain how to answer this AS Mechanics

[From: ] [author: ] [Date: 11-11-27] [Hit: ]
The balls collide after a further 2 seconds. Find the value of u.please explain in steps,s = ut + 0.s = (30 x 3) + (0.5 x -9.......
A ball is thrown vertically with a an initial velocity of 30ms^-1. One second later, another ball is thrown upwards with an initial velocity of u ms^-1. The balls collide after a further 2 seconds. Find the value of u.

please explain in steps, thank you

-
For the first ball:
s = ut + 0.5at^2
s = (30 x 3) + (0.5 x -9.81 x 3^2)
s = 45.855m = height of first ball after 3 seconds

For the second ball:
s = ut + 0.5at^2
45.855 = 2u + (0.5 x -9.81 x 2^2)
2u = 65.475
u = 32.74m/s

-
deltaX1 = (1/2)*g*t^2 + Vi*t ===> here is : t=3 sec and Vi = 30 & g=9.8
deltaX2 = (1/2)*g*t^2 + Vi*t ===> here is : t=2 sec and Vi =U & g=9.8
because the balls collide, then deltax1 = deltax2
and replace t and Vi & g , in above deltaX s ,and you can find U
:)
1
keywords: answer,this,Please,explain,Mechanics,AS,to,how,Please explain how to answer this AS Mechanics
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .