Algebra 3 question helpp

After how many seconds would car 1 and car 2 have the same amount of fuel left in their tanks?
round to the nearest second.

car 1. f(s)= 18 - 2.33(s)
car 2. f(s)= 20 - 3.06(s)

car 1. f(s)= 18 - 2.33(s)
car 2. f(s)= 20 - 3.06(s)

18 - 2.33(s)= 20 - 3.06(s)

0.73(s)=2

s=2.7=3 seconds

you set them equal and do the math

18-2.33s=20-3.06s
0.73s=2
s=2.739726...

Wtf, this is taught in algebra 3? Some class..just set the equations equal to each other

set them equal to eachother and solve for s. When i do this i get 2.739