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Evaluate the integral? Integral (5 on top, 0 on bottom) of absolute value (3x-9)
[From: ][author: ][Date: 11-11-12][Hit: ]
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int(3*x - 9, x) = (3/2)*x^2 - 9*x + C
f(x) = (3/2)*x^2 - 9*x + C
f(5) = - 15/2 + C
f(0) = C
- 15/2 + C - C = - 15/2, answer!
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