Integral/Derivative Help

So here I am, a merry little girl trying to learn some Calculus. I consider myself to be a pretty smart girl, but here I am stumped like a chump. Won't someone please help me?

Find G'(x) if.....

x
∫ 3 ln y d y
a

Won't someone please help a lady in distress? :)

x................................x
∫ 3 ln y d y=[3 y lny-3y] =3x lnx-3x-3a lna+3a=G(x)
a................................a
integral of lnx dx is x.lnx-x
G'(x)=dG(x)/dx=3 lnx+3-3=3 lnx=g(x)

You certainly don't look like a girl...