Evaluate the integral? Integral (5 on top, 0 on bottom) of absolute value (3x-9)dx

INT(0,5) [ |3x-9| dx]

With absolute value, you have to remove the bars, by redefining the function.

Since the vertex is at x=3,
|3x-9| = 3x-9, x>=3 and
= -3x+9, x<3

So split the integration into two parts:

INT(0,3)[ -3x+9] dx + INT (3,5) [3x-9] dx

Hoping this helps!

integ of (3x-9)dx= ((3x^2)/2)-9x+c
to evaluate it from 5 to 0 then

[((3*5^2)/2)-(9*5)]-[((3*0^2)/2)-(9*0)…


maybe!!!