CHEMISTRY HELP PLEASE?!?
Can someone please help me with these chem calculations I'm so lost, and it's due tomorrow, and I have no idea on what to do :'(
Alright, so, this is the data for Standard Solution 1:
0.2 M Fe(NO3)3 (in 0.1 M HNO3) : 10mL
0.001 M NaSCN (in 0.1 M HNO3) : 1 mL
0.1 M HNO3 : Dilute to 25 mL
The molar concentration of Fe(NO3)3 is 0.2 M
The molar concentration of NaSCN is 0.001 M
How do I find:
1. Volume of NaSCN (mL)
2. Moles of SCN-
3. [SCN-] (25mL)
4. [FeNcS 2+]
Please and thank you!
Can someone please help me with these chem calculations I'm so lost, and it's due tomorrow, and I have no idea on what to do :'(
Alright, so, this is the data for Standard Solution 1:
0.2 M Fe(NO3)3 (in 0.1 M HNO3) : 10mL
0.001 M NaSCN (in 0.1 M HNO3) : 1 mL
0.1 M HNO3 : Dilute to 25 mL
The molar concentration of Fe(NO3)3 is 0.2 M
The molar concentration of NaSCN is 0.001 M
How do I find:
1. Volume of NaSCN (mL)
2. Moles of SCN-
3. [SCN-] (25mL)
4. [FeNcS 2+]
Please and thank you!
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1. Volume of NaSCN (mL)
You gave this as 1 mL
2. Moles of SCN-
1 mL = 0.001 L
0.001 L X 0.001 mol/L = 1 X 10^-6 mol
3. [SCN-] (25mL)
1X10^-6 mol / 0.025 L = 4X10^-5 M
4. [FeNcS 2+]
In this solution, since there is a huge amount of iron compared to SCN-, the concentration of FeNCS will equal the concentration of SCN-. So, the answer here is 4X10^-5 M.
You gave this as 1 mL
2. Moles of SCN-
1 mL = 0.001 L
0.001 L X 0.001 mol/L = 1 X 10^-6 mol
3. [SCN-] (25mL)
1X10^-6 mol / 0.025 L = 4X10^-5 M
4. [FeNcS 2+]
In this solution, since there is a huge amount of iron compared to SCN-, the concentration of FeNCS will equal the concentration of SCN-. So, the answer here is 4X10^-5 M.
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I currently have a D in Chemistry. Can't help ya here :p