Calculus Log functions?! HELP!

Please help me understand how to solve these! Thanks!

Determine the exact value of the following expressions:
(a) log(4) + 2 log(5) (b) log_4(49) / log_4(7) (c) ln/e2

(a) uses the two principles
log(x) + log(y) = log(xy)
and p*log(x) = log(x^p)

The second of these gives
2 log(5) = log(25)

and the first gives
log(4) + log(25) = log(100)

If we take log to mean "common log", i.e. log in base 10 (not so common nowadays!!)
then
log(100) = log(10^2)
............. = 2*log(10)
............. = 2.

(b) uses the change of base rule:
log_b (a) / log_b (c) = log_c (a)
which gives us
log_7 (49)
= log_7 (7^2)
= 2

(c) I'm reading the '/' as a typo, and I'm guessing the 2 is meant to be an exponent.
(Otherwise it's ln(e*2) = ln(e) + ln(2) = 1 + ln(2))

ln(e^2) = 2*ln(e)
........... = 2.

[ a ]

... log 4 + 2( log 5 )

= log 4 + log ( 5² )

= log [ (4) x (25) ]

= log ( 10² )

= 2 ( log 10 )

= 2( 1 )

= 2 ..................................... Ans.
____________________

[ b ]

... log_4 (49) / log_4 (7)

= log_7 (49)

= log_7 ( 7² )

= 2( log_7 7 )

= 2( 1 )

= 2 ....................................... Ans.
_____________________