Genetic Traits College BIO Lab Question, please help! due tomorrow!

You want to breed dogs with black coats and long ears, tow independent traits that are controlled by completely dominant alleles (B = Black Coats, L = Long Ears). Dogs with yellow coats are bb and dogs with short ears are ll (lower case L's). You do a test breed with two dogs that are black with long ears, and of their first 8 puppies, one has a yellow coat and short ears. Now you plan on breeding this pair extensively. Answer the following four questions below:

1.) What are the Genotypes of both parent dogs?

2.)Draw a punnet square to illustrate the cross of the two parent dogs.

3.)What is the probability of any one puppy being black with long ears?

4.) If you have a dog that is black with long ears, without doing analysis of the DNA directly, how could you determine if it was homozygous or heterozygous for these traits?

Both parent dogs are heterozygous for both traits, because they got that one particular puppy.
1. Both parents are Bb Ll (last character is lower case "L")
2. It will look similar to this example (but with different letters), since we are looking at two traits, both heterozygous.
http://en.wikipedia.org/wiki/Punnett_squ…
3. Chance of black puppy : 0.75. Chance of long ears: 0.75. Combined chance: 0.75 * 0.75 = 0.5625 (you can look at the "tree method" in the above link and add the ones that have at least one R and at least one Y allele; it should be 9/16 = 0.5625)
4. Cross it with a dog that is yellow with short ears. If they have only black / long puppies, it is probably homozygous.