Solving quadratic equations by factoring. Solve the equation
1.) 8x^2+5x=2x^2=4
2.) -3b^2+3b+90=0
write the quadratic function in intercept form
1.) y=4x^2+22x+24
2.) y=16x^2-121
1.) 8x^2+5x=2x^2=4
2.) -3b^2+3b+90=0
write the quadratic function in intercept form
1.) y=4x^2+22x+24
2.) y=16x^2-121
-
1.) do you mean 8x^2+5x=2x^2+4? if so you would combine like terms then move the remaining number to that side like so: 8x^2+5x(-2x^2)= 6x^2
then, 6x^2+5x=4, 0=6x^2+5x+4 :)
then solve 2 :)
for the second part id hve to work it myself :)
then, 6x^2+5x=4, 0=6x^2+5x+4 :)
then solve 2 :)
for the second part id hve to work it myself :)
-
Just remember the song. x equals negative b plus or minus square root b squared minus 4ac all over 2a.
in the first equation, a=4, b=22, c=24. x= -22 + or - (the square root of 484-384) all over 8. so the answer will be x= -4, -3/2
in the first equation, a=4, b=22, c=24. x= -22 + or - (the square root of 484-384) all over 8. so the answer will be x= -4, -3/2
-
dont tell me what to do