Thank you
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f(x) = ln(x)
f(1) = 0
f ' (x) = 1/x
f ' (1) = 1
L(ln x ) = f (1) + f ' (1)(x - a)
= 0 + 1(x - 1)
L(ln x) = x - 1
L(ln 1.21) = 1.21 - 1 = 0.21
f(1) = 0
f ' (x) = 1/x
f ' (1) = 1
L(ln x ) = f (1) + f ' (1)(x - a)
= 0 + 1(x - 1)
L(ln x) = x - 1
L(ln 1.21) = 1.21 - 1 = 0.21
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turn to the section on Taylor series in your textbook. it probably even has the answer. i know this webpage has the answer
http://en.wikipedia.org/wiki/Taylor_seri…
but it doesn't show the work for arriving at it for your particular problem. that's why it's YOUR homework.
http://en.wikipedia.org/wiki/Taylor_seri…
but it doesn't show the work for arriving at it for your particular problem. that's why it's YOUR homework.
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res