Evaluate expressions help.

Can someone explain how to find x that satisfies the equation:
^=exponent

2 ^3-x=4 ^x

or
(2.14)^x-1= (2.14)^1-x

i dont need the answer, just an explanation on how to complete them, any help thanks

Assuming you meant 2^(3-x), then turn 4^x into 2^(2x). Take the log base 2 of both sides, you're left with 3-x = 2x, or x=1.

The second one, take the log base 2.14 of both sides, you get x-1 = 1-x.

2x=2, or x=1.

Hope that helps :)

You need logarithms to solve these.

For the first one, you have 2^(3-x) = 2*2^x

If you take the logarithm to the base 2 of both sides you will get

3-x = 2x

3x = 3 ---> x=1

Just check that it works by substituting it in for x in the original equation

2^(3-1) =4^1

2^2 = 4 So yep, that works.