Help on this math problem

ineed help on this.. im not sure whether to distribute or do it some way else?:s

Solve the equation 7 = 2 + 5(z - 2)
A. 3
B. 5
C. -3

Can someone explain to me how to do this... like the steps and whatnot...


Thanx!!<3

First multiply the 5 times the (z - 2) term to get:

7 = 2 + 5z - 10

Combine like terms (add the 2 and -10)

7 = -8 + 5z

Add 8 to both sides:

15 = 5z

Divide both sides by 5:

z = 3

You need to multiply out everything within the brackets first.

7 = 2 + 5z - 10

Now you need to get all the zs on the left, and everything else on the right.

7 - 5z = 2 - 10 (subtract 5 z from both sides)
-5z = 2 - 10 - 7 (subtract 7 from each side)
-5z = -15 (2 - 10 - 7= -15)
z = -15/-5 (divide both sides by -5)
z = 3 (-15/-5 = 3)

7 = 2 + 5(z - 2)
distribute 5(z - 2)
7 = 2 + 5z - 10
isolate the z to one side.
5z = 7 - 2 + 10.
5z = 15
z = 3.

A

7=2+5z-10....add 8 to b
oth sides

7+8=5z
15=5z div by 5
z=3 ans is 3 ck 7= 2+5(3-2) 7=7 answer ck so answer ck ou.

a.3

7=2+5(z-2) implies 7-2=5(z-2) so 5=5(z-2) so 1=z-2 so z=1+2=3.

I wish I could help but im not quite sure. :(