How is a balanced chemical equation used in titration calculations?
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It is used in the normal titration calculations via this relationship.
Suppose substance A reacts with substance B, then:
Moles of A in eqtn/moles of B in eqtn = vol x molarity A/ vol x molarity B
It is vital that the original equation is correctly balanced
Suppose substance A reacts with substance B, then:
Moles of A in eqtn/moles of B in eqtn = vol x molarity A/ vol x molarity B
It is vital that the original equation is correctly balanced
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You have to know why you are doing the titration, and the relationships of the reactants, and to make sure you are using the proper indicator to enable you to find the equivalence point.
For example: H3PO4 + 3NaOH --> Na3PO4 + 3 H2O.
The ratios are indicated and the type of acid and base used..
For example: H3PO4 + 3NaOH --> Na3PO4 + 3 H2O.
The ratios are indicated and the type of acid and base used..