Find the derivative f(x) = 5^x
You may need to use logarithmic differentiation
You may need to use logarithmic differentiation
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lets call f(x) y and f'(x) y'
y = 5^x
you take the natural log of both sides to get rid of the x in the exponent
lny = xln5
then you take the derivative of both sides
1/y(y') = 1(ln5) + 0(x)
then you multiply both sides by y to get y' by itself
y' = y(ln5)
then you plug in y
y' = (ln5)(5^x)
y = 5^x
you take the natural log of both sides to get rid of the x in the exponent
lny = xln5
then you take the derivative of both sides
1/y(y') = 1(ln5) + 0(x)
then you multiply both sides by y to get y' by itself
y' = y(ln5)
then you plug in y
y' = (ln5)(5^x)
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Let f(x) be y
y= 5^x
lny= ln5^x
yprime/y= x/5
Yprime= y(x/5)
Yprime is another way of saying derivative (y')
y= 5^x
lny= ln5^x
yprime/y= x/5
Yprime= y(x/5)
Yprime is another way of saying derivative (y')
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f(x)=a^x
d/dx f(x)=a^x ln(a)
good luck my friend
d/dx f(x)=a^x ln(a)
good luck my friend