...through the point (-3,2) that is perpendicular to the line < -3-2t , 5t-2 >
L(t) = ?
L(t) = ?
-
Line < -3-2t, 5t-2 > = < -3, -2 > + t < -2, 5 >
Line perpendicular to this line will have direction vector: < 5, 2 >
Since this line passes through point (-3,2), we get:
L(t) = < -3, 2 > + t < 5, 2 >
L(t) = < 5t - 3, 2t + 2 >
Mαthmφm
Line perpendicular to this line will have direction vector: < 5, 2 >
Since this line passes through point (-3,2), we get:
L(t) = < -3, 2 > + t < 5, 2 >
L(t) = < 5t - 3, 2t + 2 >
Mαthmφm