How could you solve this 38h^3+h^2-5=0 what is the value of h show me the steps.
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How could you solve this 38h^3+h^2-5=0 what is the value of h show me the steps.

[From: ] [author: ] [Date: 11-10-27] [Hit: ]
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38h^3+h^2-5=0
(2h-1) is the factor
the final answer is 1/2
digout

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it factors into (2 h-1) (19 h^2+10 h+5) = 0
then you can set each polynomial equal to zero, you only end up with one real solution
1
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