Algebra distribution problem

(0.381)(0.05-2x)=x
ok so for x my teacher gets x=0.011 I do not see how he got that please help!!

Compute brackets, remember that: (a+b)(c+d) = ac+ad+bc+bd = (a+b)c + b(c+d).
(0.381)(0.05-2x)=x
0.381*0.05 - 0.381*(-2x) = x
0.01905-0.762x = x. Add 0.762x to both sides of the equation.
Then:
0.01905-0.762x +0.762x = x+0.762x
0.01905 = 1.762x
x = 0.01905/1.762 = 0.0108115778.
Rounding off gives 0.011.

So, you're looking for what x equals.
To find x:

step 1: distribute the left side of the equation
result: .01905 - .762x = x

step 2: combine like terms by adding the .762x from both sides of the equation
result: .01905 = 1.762x

final step: isolating x by dividing both sides of the equation by 1.762
result: .01081 = x

your teacher rounded to 3 decimal places, which brought .01081 up to .011

Take it one step at a time =)

First, multiply 0.381 x 0.05 = 0.01905

Now, multiply 0.381 x -2x= -0.762x

Then, subtract -0.762x from both sides (remember, when you subtract a negative, you are actually adding----two negatives make a positive.) So you actually add 0.762x to 1x, which gives 1.762x

Now divide each side by 1.762, in order to isolate the x term, which will look like 1.762x=0.01905


Your teacher is correct, the sign is correct and the number is correct. I promise I know what I am talking about. I am a Biochemistry major, and I have taken up to Vector Calculus.

Lastly, divide by 1.762: 0.01905/1.762 = 0.0108, which rounds up to 0.011

First.. let's use an easier problem to show you how to distribute. Let's say...
(2)(1-2x)=x

When distributing you, are just multiplying both 1 and -2x by 2.. so you would get this..
2-4x=x

Now with this you solve for x.. so you add 4x to each side.
2-4x+4x=x+4x