Quadratic Function Question.
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Quadratic Function Question.

[From: ] [author: ] [Date: 11-10-27] [Hit: ]
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A rectangular field with an area of 8000m² is enclosed by 400 m of fencing. Determine the dimensions of the field to the nearest tenth of a metre.

It has to be solved using a quadratic equation.

-
L+W=200
LW=8000
L+8000/L-200=0
L^2-200L+8000=0
From the quadratic formuls
L = 144.72 m
W = 55.28
Field is 144.7 by 55.2 metres

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Area = l * w = 8000 m^2

Perimeter = 2l + 2w = 400 m

l = 200 - w

substitute: (200 - w) * w = 8000

solve the quadratic...

200w - w^2 = 8000

w^2 - 200w + 8000 = 0

w = [200 ± √(8000)]/2 = 100 ± 20√5 m

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