Mean Value theorem? Full points will be awarded!
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > Mean Value theorem? Full points will be awarded!

Mean Value theorem? Full points will be awarded!

[From: ] [author: ] [Date: 11-10-25] [Hit: ]
for the first question, i got - 3 and for the second question, i got 1/2. Is this right? If not, how did you get your answer?......
So, f(x) = -3x^2 + 4 on interval [-1, 2]. what value of f ' (x) does the MVT assure us exists? at what point does it exist? for the first question, i got - 3 and for the second question, i got 1/2. Is this right? If not, how did you get your answer?

-
f'(c) = f(b) - f(a) / (b-a)

f'(x) = -6x

-6x = -8 - (1) / (3)

-6x = -9 / 3

6x = 3
x = 1/2 (Where it exists)

What value it is f'(x) = secant line = -6x = -3.

Good job.
1
keywords: Value,will,Mean,points,awarded,be,theorem,Full,Mean Value theorem? Full points will be awarded!
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .