How do you solve -3x=2

Can anyone help me?
How do you solve -3x=2 and -3x=1/3. How to solve x?

Like the last guy said you start by dividing by the number in front of the x. When it comes to dividing a fraction though its easier to invert the first number and multiply as follows

-3x = 1/3
x = (1/3) / -(3/1)
x = 1/3 * -1/3
When you multiply fractions you just do it straight across so you multiply 1 by -1 to get -1 then you multiply 3 by -3 to get -9. That is how you get:
x = -1/9


The first one is much easier

-3x = 2
x = 2/-3 or -2/3

This is very easy.
Divide the coefficient on the left (in this case, -3) and the amount on the right by the coefficient for the left, so you would divide -3x by -3 and 2 by 3, giving you x=-2/3 (negative two-thirds)

Second problem: -3x=1/3
Divide -3x by -3
Divide 1/3 by 3
x=-1/9 (negative one-ninth)

You divide by whatever number is in front of the x. In that first one, you'll divide both 3x and 2 by 3 and you'll get c = -2/3.
For the second one do the same thing and you'll get -1/9

you divide the 2 by -3 for the first one and one over -3 times 3 for the second one(the second one is equal to -1/9 )

-3x=2
-x=2/3,x=-2/3,similarly
-3x=1/3
-x=(1/3x3)=1/9
x=-1/9

-3x=2
divide both side by -3
x=-2/3

-3x=1/3
dividing both side by -3
x= -1/9

-3x=2

-x = 2/3

x = -2/3


-3x = 1/3

-x = 1/9

x = -1/9

-3x=2
or, 3x=-2
or, x=-2/3

-3x=1/3
or,3x=-1/3
or, x=-1/9