How would I compute the mean and standard deviation given n= 9, p= 0.75
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How would I compute the mean and standard deviation given n= 9, p= 0.75

[From: ] [author: ] [Date: 11-10-12] [Hit: ]
The standard deviation is the square root of the variance,n*p*(1-p)=9*.75*.25=1.6875so the std dev is sqrt(1.6875)=1.......
Can you explain everything, don't really understand thankyou

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Yeah. Its binomial. so there is .75 percent chance of sucess. Their are nine trials, so we expect .75*9=6.75 successes on average.

The standard deviation is the square root of the variance, which for binomial is

n*p*(1-p)=9*.75*.25=1.6875
so the std dev is sqrt(1.6875)=1.29903
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