Please help!
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Y = x^2 + 6x - 20 is a parabola opening up.
It is in standard form, y = ax^2 + bx + c
A quick peek at the discriminant, b^2 - 4ac,
6^2 - 4(2)(- 20) = 36 + 160 = 196, lets us know it has two real roots.
To solve, factor using FOIL.
2x^2 + 6x - 20 = 0
All terms are multiples of two, so factor it out.
2(x^2 + 3 - 10) = 0
2(x + 5)(x - 2) = 0
x = - 5, x = 2
It is in standard form, y = ax^2 + bx + c
A quick peek at the discriminant, b^2 - 4ac,
6^2 - 4(2)(- 20) = 36 + 160 = 196, lets us know it has two real roots.
To solve, factor using FOIL.
2x^2 + 6x - 20 = 0
All terms are multiples of two, so factor it out.
2(x^2 + 3 - 10) = 0
2(x + 5)(x - 2) = 0
x = - 5, x = 2
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y = 2x^ + 6x – 20
DEFINITION:
The x-intercept(s) of the parabola (e.g. YOUR FUNCTION ABOVE) is/are the ( x, y ) coordinates of the point(s) of the parabola where it intersects the x-axis. The y-value of the x-intercept(s) is always 0, if an x-intercept exists. If an x-intercept does not exist, then there are NO coordinates for an x-intercept.
step 1) set y = 0 to find x-intercepts
step 2) 0 = 2x^2 + 6x - 20
step 3) factor out 2 from the right side => 2(x^2 + 3 - 10) = 0
step 4) divide both sides by 2 ===> x^2 + 3 - 10 = 0
step 5) factor out the quadratic equation: (x + 5) (x - 2) = 0
step 6) set each factor to zero
x + 5 = 0 ==> x = -5
x - 2 = 0 ==> x = 2
step 7) since the y=0 for any x-intercept the coordinates or your x-intercepts are:
(-5, 0) and (2, 0)
I explained it in detail so you may learn the procedure and solve future similar problems on your own. Hope it is helpful.
DEFINITION:
The x-intercept(s) of the parabola (e.g. YOUR FUNCTION ABOVE) is/are the ( x, y ) coordinates of the point(s) of the parabola where it intersects the x-axis. The y-value of the x-intercept(s) is always 0, if an x-intercept exists. If an x-intercept does not exist, then there are NO coordinates for an x-intercept.
step 1) set y = 0 to find x-intercepts
step 2) 0 = 2x^2 + 6x - 20
step 3) factor out 2 from the right side => 2(x^2 + 3 - 10) = 0
step 4) divide both sides by 2 ===> x^2 + 3 - 10 = 0
step 5) factor out the quadratic equation: (x + 5) (x - 2) = 0
step 6) set each factor to zero
x + 5 = 0 ==> x = -5
x - 2 = 0 ==> x = 2
step 7) since the y=0 for any x-intercept the coordinates or your x-intercepts are:
(-5, 0) and (2, 0)
I explained it in detail so you may learn the procedure and solve future similar problems on your own. Hope it is helpful.
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2(x+5)(x-2)=0---->x=...