A goldsmith mixed 10 grams of a 50% gold alloy with 40 grams of 15% gold alloy. What is the percent concentration of the resulting alloy?
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50/100 x 10 = 5 GRAMS
15/100 x40 = 6 GRAMS
ADD = 11 GRAMS
11 /50 x 100 = 22% answer
15/100 x40 = 6 GRAMS
ADD = 11 GRAMS
11 /50 x 100 = 22% answer
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a = alloy concentration
a = (10g * 0.5) + (40g * 0.15)
a = 5g + 6g
a = 11g
11g / (10g + 40g) = 11g / 50 g
= 0.22
= 22%
a = (10g * 0.5) + (40g * 0.15)
a = 5g + 6g
a = 11g
11g / (10g + 40g) = 11g / 50 g
= 0.22
= 22%
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22%