ive been doing practice questions all day and doing fine but I cannot seem to get this one. can anyone help?
Solve the given linear system
6u − v = 0
– 8u + 4v = 0
8u − 2v = 0
Solve the given linear system
6u − v = 0
– 8u + 4v = 0
8u − 2v = 0
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Hi Chuckie.
Let me arrange the 3 into equations 1-3.
1) 6u − v = 0
2) 4v – 8u = 0
3) 8u − 2v = 0
Arrange 1) into v = 6u
Sub v=6u in both equation 2 and 3.
2) 4(6u) - 8u = 0
16u = 0
3) 8u - 2(6u) = 0
-4u = 0
Now hold on, this means u = 0 since it's consistent in both equation 2 and 3. Sub u = 0 for any equation, let's say 2).
4v -8(0) = 0
v = 0
Therefore, both u and v are = 0.
Hope this helps. :D
Let me arrange the 3 into equations 1-3.
1) 6u − v = 0
2) 4v – 8u = 0
3) 8u − 2v = 0
Arrange 1) into v = 6u
Sub v=6u in both equation 2 and 3.
2) 4(6u) - 8u = 0
16u = 0
3) 8u - 2(6u) = 0
-4u = 0
Now hold on, this means u = 0 since it's consistent in both equation 2 and 3. Sub u = 0 for any equation, let's say 2).
4v -8(0) = 0
v = 0
Therefore, both u and v are = 0.
Hope this helps. :D
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u=v=0