For example, CH3CCCH2CH3. I can draw the lewis structure but I'm having trouble telling which atoms are collinear. How can you tell without using a molecule kit?
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H3C-C:::C-CH2-CH3
Triple bonds are always at 180* to the other single bond on the carbon. So the portion that is colinear is: C-C:::C-C
The first 4 carbons are colinear. The CH2 group (carbon 4) is trigonal planar, so the last CH3 group is at 120* to the other carbons.
Another example is Acetylene H-C:::C-H wher all atoms are colinear.
Also, when 2 double bonds are on the same carbon (conjoined), the other double bonded atoms are colinear.
Examples are: Carbon Dioxide (O=C=O), and Propadiene (H2C=C=CH2).
Triple bonds are always at 180* to the other single bond on the carbon. So the portion that is colinear is: C-C:::C-C
The first 4 carbons are colinear. The CH2 group (carbon 4) is trigonal planar, so the last CH3 group is at 120* to the other carbons.
Another example is Acetylene H-C:::C-H wher all atoms are colinear.
Also, when 2 double bonds are on the same carbon (conjoined), the other double bonded atoms are colinear.
Examples are: Carbon Dioxide (O=C=O), and Propadiene (H2C=C=CH2).