The problem states: Using the fact that the square root (k), with k in positive integers, is a rational number if and only if k is a square, prove that the square root (9n+6n+4) is irrational for all n in positive integers.
I have put in some values of n to find out that this is not true when n=3, n=4, n=13, n=17 and there are probably others as well. So how would I prove this is true all the time? Any help will be greatly appreciated. Thanks.
I have put in some values of n to find out that this is not true when n=3, n=4, n=13, n=17 and there are probably others as well. So how would I prove this is true all the time? Any help will be greatly appreciated. Thanks.
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n = 3, 4, 13....etc are your counterexamples. There could be no proof.
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Is it suppose to be 9n^2 + 6n +4?
Cause this will only give you (9n+6n+4) = 15n + 4
Cause this will only give you (9n+6n+4) = 15n + 4