1. how do i simplify the expression (-6i)(-6i)?
i got 36i, am i right?
2. (2+5i)(-1+5i)
i got 23+5i
i got 36i, am i right?
2. (2+5i)(-1+5i)
i got 23+5i
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1. remember that i^2 = -1
so (-6i)(-6i) = 36i^2 = -36
2. (2 + 5i)(-1 + 5i) = -2 + 10i - 5i + 25i^2
= -2 - 25 + 5i = -27 + 5i
(2 + 5i)(-1 + 5i) = -27 + 5i
so (-6i)(-6i) = 36i^2 = -36
2. (2 + 5i)(-1 + 5i) = -2 + 10i - 5i + 25i^2
= -2 - 25 + 5i = -27 + 5i
(2 + 5i)(-1 + 5i) = -27 + 5i
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Remember that i^2 = -1. Use that substitution wherever you can.
1.
(-6i)(-6i)
= 36i^2
= 36 (-1)
= -36
2.
(2+5i)(-1+5i)
= -2 - 5i + 10i + 25i^2
= -2 +5i +25(-1)
= -2 + 5i - 25
= 5i - 27
1.
(-6i)(-6i)
= 36i^2
= 36 (-1)
= -36
2.
(2+5i)(-1+5i)
= -2 - 5i + 10i + 25i^2
= -2 +5i +25(-1)
= -2 + 5i - 25
= 5i - 27
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(-6i)^2
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Q1. No, it is 36i² = 36 x -1 = -36
Q2. (2+5i)(-1+5i)
= -2 +10i -5i + 25i²
= -2 + 5i - 25
= -27 + 5i
Q2. (2+5i)(-1+5i)
= -2 +10i -5i + 25i²
= -2 + 5i - 25
= -27 + 5i
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The first one's right, but I think the second is -2+25i ? Hope this helps;)