More algebra questions..

James exercises by bicycling. after t minutes , he is 0.25t+17 miles from home. In how many minutes is James 38 miles from home?

A 76 min
B 17 min
C 152 min
D 84 min

Could you please explain it too, because I don't get it and no one helps me with this stuff

Solve for P. W= P-2L/2

a.) p=1/2w+2L
b.) p=2w-2L
c.) p=2w+2L
d.) p=-2L - 2w

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the length and width of a bedroom floor are 11 meters. the height of the ceiling is 5 meters, to the nearest tenth, find the distance from one corner on the floor of the room to the corner on the ceiling diagonally opposite.

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the longer side of a parellogram is 6 meters longer than the shorter side. The perimeter is 44 meters. Whats the length of the longer side?

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solve -3 >= -3x + 4 > 10

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a highway has a maximum speed of 70 miles per hour and a minimum speed of 45 miles per hour. if x represents the speed, which sentence expresses the condition?

70 <= x <= 45

45x<70

70 => x => 45

70 => x and x <= 45

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Solve |x+5| < 7

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Solve |3x-1| <= 4

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The width of a new window must be within 1/4 inch of the width of the window opening. A hardware store sells windows that 3 and 3/4 feet wide.Which of the following inequalities expresses the range of widths for window openings?

|x+45| < 1/4

|x-45| < 1/4

|x- 3 and 1/4| < 1/4

|x+ 1/4| < 3 and 1/4

1)
distance, d = 0.25t+17 miles

For, d= 38 miles = 0.25t +17
0.25t = 38 -17 = 21
t = 21/0.25 = 84 minutes
SO,
Answer is : D 84 min >==============< ANSWER

2)
Solve for P. W= (P-2L)/2

2W = P - 2L
P = 2W + 2L
SO,
Answer is :c.) p = 2w+2L >=================< ANSWER

3)
lengt, l = 11 m,
width, w = 11 m,
height, h = 5 m
Floor-diagonal = sqrt[11^2 + 11^2] = sqrt(242) m

Required-diagonal = sqrt[242 + 5^2] = sqrt[267]

= 16.34 meters >=========================< ANSWER

Similaly Solve the other questions....................