Write an equation for a line that includes the point (-7,6) and is parallel to the line 4x+2y=9
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First you have to find the slope of the equation:
4x + 2y = 9
2y = -4x + 9
y = -2x + 9/2
The slope is -2.
Next, you have to find the y-intercept.
(-7,6) Substitute the points in an equation:
6 = -2(-7) + b
6 = 14 + b
-8 = b
So the y-intercept is -8.
Lastly, set up the equation with the slop and y-intercept that we just found.
y = -2x - 8
4x + 2y = 9
2y = -4x + 9
y = -2x + 9/2
The slope is -2.
Next, you have to find the y-intercept.
(-7,6) Substitute the points in an equation:
6 = -2(-7) + b
6 = 14 + b
-8 = b
So the y-intercept is -8.
Lastly, set up the equation with the slop and y-intercept that we just found.
y = -2x - 8
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First, find the slope of the line 4x+2y=9 in order to plug things in.
2y=-4x+9
y=-2x+9/2
The slope is -2.
Now, plug in the points into the point slope form.
For parallel lines, the slope has to be the same.
Also, to have that line go through certain points, just plug those points into the equation below:
y1-y=m(x1-x) *m=slope
6-y=-2(-7-x) *In this case, x=-7 & y=6
6-y=14+2x
y=-2x-8
And to check your answer, plug in the points into your answer(;
^-^ Hope it helped
2y=-4x+9
y=-2x+9/2
The slope is -2.
Now, plug in the points into the point slope form.
For parallel lines, the slope has to be the same.
Also, to have that line go through certain points, just plug those points into the equation below:
y1-y=m(x1-x) *m=slope
6-y=-2(-7-x) *In this case, x=-7 & y=6
6-y=14+2x
y=-2x-8
And to check your answer, plug in the points into your answer(;
^-^ Hope it helped
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Y=-2X-8
first you put the problem into slope intercept form and make it y=-2X+4.5
Then you supsitute the poin (-7,6) into the equation as x and y and make it 6=(-7)-2+b
The 4.5 is replaced with b because if it is parallel the second line cannot have the same y intercept as the first. Then you solve for b and get -8. And plug the -8 into the y intercept form insted of 4.5 and get y=-2x -8
first you put the problem into slope intercept form and make it y=-2X+4.5
Then you supsitute the poin (-7,6) into the equation as x and y and make it 6=(-7)-2+b
The 4.5 is replaced with b because if it is parallel the second line cannot have the same y intercept as the first. Then you solve for b and get -8. And plug the -8 into the y intercept form insted of 4.5 and get y=-2x -8
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4x + 2y = 9
2y = - 4x + 9
y = - 2x + 9/2
slope of existing line is - 2. A parallel line has the same slope. We can substitute that into
y = mx + b and get
y = - 2x + b
Now sub the point into the equation and solve for b and we get
6 = - 2(- 7) + b
6 = 14 + b
- 8 = b
so we have
y = - 2x - 8
2y = - 4x + 9
y = - 2x + 9/2
slope of existing line is - 2. A parallel line has the same slope. We can substitute that into
y = mx + b and get
y = - 2x + b
Now sub the point into the equation and solve for b and we get
6 = - 2(- 7) + b
6 = 14 + b
- 8 = b
so we have
y = - 2x - 8
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First determine slope of the 4x + 2y = 9. Re-arrange as 2y = -4x + 9, so y = -2x +9/2. The slope is -2.
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