(2x-1)/((x+2)(x^2 + 3)) = 0
Answer is
X=-1/2
Please show how to get to the answer and only post if you really know youre correct.
It seems i can only get one person to answer on math questions, after the first person, no one bothers.
Answer is
X=-1/2
Please show how to get to the answer and only post if you really know youre correct.
It seems i can only get one person to answer on math questions, after the first person, no one bothers.
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> (2x-1)/((x+2)(x^2 + 3)) = 0
I assume the intent is to solve over the reals.
multiply both sides by the denominator, giving
(2x-1) = 0 . ((x+2)(x^2 + 3)) . . . (as long as x ≠ -2 )
therefore
(2x - 1) = 0
2x = 1
x = 1/2
The answer is not what you said. Did you type the question wrong or the answer wrong?
> It seems i can only get one person to answer on math questions, after the first person, no one bothers.
If you spent much time answering questions here you'd very quickly figure out why. Blame the way yahoo has the system set up. There's little point in answering answered questions because there's little relative reward for not getting 'best answer'.
I assume the intent is to solve over the reals.
multiply both sides by the denominator, giving
(2x-1) = 0 . ((x+2)(x^2 + 3)) . . . (as long as x ≠ -2 )
therefore
(2x - 1) = 0
2x = 1
x = 1/2
The answer is not what you said. Did you type the question wrong or the answer wrong?
> It seems i can only get one person to answer on math questions, after the first person, no one bothers.
If you spent much time answering questions here you'd very quickly figure out why. Blame the way yahoo has the system set up. There's little point in answering answered questions because there's little relative reward for not getting 'best answer'.
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Well, how many answers do you want ? If the first answer is a good one, what is the point of it being endlessly repeated ?
(2 x- 1) / ((x + 2) (x^2 + 3)) = 0
Multiply by the denominator , which gives you
2x - 1 = 0
hence 2x = 1
x = 1/2 (NOT -1/2)
Actually, if any fraction of any sort is shown as = 0, then the numerator itself MUST = 0. The denominator is irrelevant in such a case.
(2 x- 1) / ((x + 2) (x^2 + 3)) = 0
Multiply by the denominator , which gives you
2x - 1 = 0
hence 2x = 1
x = 1/2 (NOT -1/2)
Actually, if any fraction of any sort is shown as = 0, then the numerator itself MUST = 0. The denominator is irrelevant in such a case.
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If you want better responses, you might try being more polite and less demanding with how you want people to answer lol, I mean: http://answers.yahoo.com/question/index;… , seriously?
As the other two answerers have stated, the answer is x = 1/2, no negative about it. If you do not believe us, put in x = -1/2, and you will not get zero.
(2x-1)/((x+2)(x^2 + 3)) = 0
means (2x - 1) = 0
2(x - 1/2) = 0
x - 1/2 = 0
x = 1/2
As the other two answerers have stated, the answer is x = 1/2, no negative about it. If you do not believe us, put in x = -1/2, and you will not get zero.
(2x-1)/((x+2)(x^2 + 3)) = 0
means (2x - 1) = 0
2(x - 1/2) = 0
x - 1/2 = 0
x = 1/2