please show all work!
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use Pythagorian's
side of the triangle =s
s²=(6√3)²+(s/2)²
solve for s
P=3s
side of the triangle =s
s²=(6√3)²+(s/2)²
solve for s
P=3s
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The altitude divides the equilateral triangle into two 30-60-90 triangles.
The sides of the 30-60-90 triangle are proportional to 1 (base), 2 (hypotenuse), sqrt(3) (altitude).
The altitude of your triangle is 6sqrt(3). Multiply the hypotenuse by 6 to get the length of one side.
Your perimeter is 36.
The sides of the 30-60-90 triangle are proportional to 1 (base), 2 (hypotenuse), sqrt(3) (altitude).
The altitude of your triangle is 6sqrt(3). Multiply the hypotenuse by 6 to get the length of one side.
Your perimeter is 36.
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Let s be a side of the equilateral triangle.
s√3/2 = 6√3
s = 12
Perimeter = (12)(3) = 36
s√3/2 = 6√3
s = 12
Perimeter = (12)(3) = 36