Here is the question, For a school fundraiser, jay sold 12 boxes of stationery and 8 boxes of envelopes for a total of $41.00. sue sold 18 boxes of stationery and 16 boxes of envelopes for $68.50. How much did one box of envelopes cost? Can anyone help and explain this please? I have no clue how to do this cuz my teacher didnt show us how.
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let consider cost of one box of stationery be x and one box of envelope be y.
Then, from question, we can have an equation,
12x + 8y =$41.00..............................(i)
18x + 16y =$68.50.............................(ii)
Multiply equation (i) by 3 and multiply equation (ii) by 2. Then subtract (ii) form (i). You will have,
8y = $14.00
y = $1.75.
So cost for one box of envelope is $1.75
Then, from question, we can have an equation,
12x + 8y =$41.00..............................(i)
18x + 16y =$68.50.............................(ii)
Multiply equation (i) by 3 and multiply equation (ii) by 2. Then subtract (ii) form (i). You will have,
8y = $14.00
y = $1.75.
So cost for one box of envelope is $1.75
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ok well first, you have to find out what 's' is (stationary box cost) so this wud make a simulateous equation.
s= stationary boxes e= envelope boxes
1) 12s + 8e= 41 (equation 1)
18s + 16e= 68.5 (equation 2)
2) Multiply equation 1 by 8 and equation 2 by 16 so they both have the same number
12s + 128e= 41
18s + 128e= 68.5
3) Move the unknowns onto the other side of the equation by taking them away
128e = 41 - 12s
128e = 68.5 - 18s
4) since both equations equal 128e, it makes sense to write it out like this:
41 - 12s = 68.5 - 18s
5) now take away the smaller unknown (-12) from the bigger unknown (-18) by adding +12 to both unknowns to get rid of it: (+12 - 12= 0) (+12 -18 = -6)
41= 68.5 - 6s
6) Now take away 68.5 on both sides (41 - 68.5 and 68.5 - 68.5)
-27.5= -6s or -6s= -27.5
7) Now divide -27.5 by -6
s= $4.50
to find out 'e', substitute 's' in the previous equation with 4.5
12(X 4.5) + 8e= 41
18(X4.5) + 16e= 68.5
54+ 8e=41
81+16e= 68.5
Minus 41 and 68.5 on both sides
13 + 8e= 0
12.5 + 16e = 0
move 8 and 16 onto the other side..
13= -8e
12.5= -16e
now divide 13 by 8...
$1.75= e
Long but helps in ALL simultaneous equations!
Hope this helped x
s= stationary boxes e= envelope boxes
1) 12s + 8e= 41 (equation 1)
18s + 16e= 68.5 (equation 2)
2) Multiply equation 1 by 8 and equation 2 by 16 so they both have the same number
12s + 128e= 41
18s + 128e= 68.5
3) Move the unknowns onto the other side of the equation by taking them away
128e = 41 - 12s
128e = 68.5 - 18s
4) since both equations equal 128e, it makes sense to write it out like this:
41 - 12s = 68.5 - 18s
5) now take away the smaller unknown (-12) from the bigger unknown (-18) by adding +12 to both unknowns to get rid of it: (+12 - 12= 0) (+12 -18 = -6)
41= 68.5 - 6s
6) Now take away 68.5 on both sides (41 - 68.5 and 68.5 - 68.5)
-27.5= -6s or -6s= -27.5
7) Now divide -27.5 by -6
s= $4.50
to find out 'e', substitute 's' in the previous equation with 4.5
12(X 4.5) + 8e= 41
18(X4.5) + 16e= 68.5
54+ 8e=41
81+16e= 68.5
Minus 41 and 68.5 on both sides
13 + 8e= 0
12.5 + 16e = 0
move 8 and 16 onto the other side..
13= -8e
12.5= -16e
now divide 13 by 8...
$1.75= e
Long but helps in ALL simultaneous equations!
Hope this helped x
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Set up an equation.
x-Stationary.
y-Envelopes.
12x + 8y = $41.00.
18x+ 16y=$68.50.
The mulitply your first equation by -2.
So you get -24x - 16y=-$48.00.
then you cancel it out,
so you get -6x=$20.50
Lol yeah idk if i'm right or not. but i'm pretty sure.
x-Stationary.
y-Envelopes.
12x + 8y = $41.00.
18x+ 16y=$68.50.
The mulitply your first equation by -2.
So you get -24x - 16y=-$48.00.
then you cancel it out,
so you get -6x=$20.50
Lol yeah idk if i'm right or not. but i'm pretty sure.
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12S + 8E = 41 times 2 makes 24S + 16E = 82
18S +16E = 68.5 subtract equations
6S = 13.5
S = $2.25 now substitute
E = $1.75
18S +16E = 68.5 subtract equations
6S = 13.5
S = $2.25 now substitute
E = $1.75
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thats what Internet is for