Find (f(x-h)-f(x))/h for the function f(x)=x/(x+1)
So far, I got [((x+h)/(x+h+1)) - (x/(x+1))] /h
I'm stuck from there.
Any help would be appreciated.
So far, I got [((x+h)/(x+h+1)) - (x/(x+1))] /h
I'm stuck from there.
Any help would be appreciated.
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You are doing good so far. At this point, clear the denominators in the numerator by multiplying the numerator and the denominator of the whole fraction by (x + 1)(x + h + 1). This gives:
[(x + h)/(x + h + 1) - x/(x + 1)]/h
= [(x + h)(x + 1) - x(x + h + 1)]/[h(x + 1)(x + h + 1)]
= [(x^2 + x + xh + h) - (x^2 + xh + x)]/[h(x + 1)(x + h + 1)], by expanding
= h/[h(x + 1)(x + h + 1)], by simplifying
= 1/[(x + 1)(x + h + 1)], by canceling h.
I hope this helps!
[(x + h)/(x + h + 1) - x/(x + 1)]/h
= [(x + h)(x + 1) - x(x + h + 1)]/[h(x + 1)(x + h + 1)]
= [(x^2 + x + xh + h) - (x^2 + xh + x)]/[h(x + 1)(x + h + 1)], by expanding
= h/[h(x + 1)(x + h + 1)], by simplifying
= 1/[(x + 1)(x + h + 1)], by canceling h.
I hope this helps!
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f(x) = x / (x+1)
f(x+h) = x+h / x + h + 1
f(x+h) - f(x) = x + h / x + h + 1 - x / x + 1
= [(x+h)(x+1) - (x+h+1)x] / (x+1)(x+h+1)
= x^2 + x + hx + h - x^2 - hx - x / (x+1)(x+h+1)
= h / (x+1)(x+h+1)
So f(x+h) - f(x) / h = 1 / (x+1)(x+h+1)
f(x+h) = x+h / x + h + 1
f(x+h) - f(x) = x + h / x + h + 1 - x / x + 1
= [(x+h)(x+1) - (x+h+1)x] / (x+1)(x+h+1)
= x^2 + x + hx + h - x^2 - hx - x / (x+1)(x+h+1)
= h / (x+1)(x+h+1)
So f(x+h) - f(x) / h = 1 / (x+1)(x+h+1)
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f(x h)-fx/h
its nothing but slope dy/dx at some point.
y=x/x 1
differentiating both sides we get,
dy/dx=1/(x 1) x/(x 1)^2
thats the answer(by shortcut)
its nothing but slope dy/dx at some point.
y=x/x 1
differentiating both sides we get,
dy/dx=1/(x 1) x/(x 1)^2
thats the answer(by shortcut)