Super easy algebra word problem

..for those that are decent at math at least.

My answer for wind is 6mph and I'm wondering if I'm right.

here's the problem"


A cyclist travels 48km in 2 hours going against the wind. She travels 60km with the wind in the same amount of time. What is the rate of the cyclist in still air and what is the rate of the wind?

use Distance=rate*time

48=(rate of cyclist-rate of wind)*2.....24=(rate of cyclist-rate of wind)

60=(rate of cyclist+rate of wind)*2....30=(rate of cyclist+rate of wind)

Let x be rate of cyclist and y be the rate of wind

24=x-y
30=x+y

Linear combination.

54=2x
x=27

24=27-y
y=3

rate of cyclist= 27 km/ hr
rate of wind=3km/hr