Tricky math word problem, please help!
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Tricky math word problem, please help!

[From: ] [author: ] [Date: 11-06-22] [Hit: ]
-Break it down one step at a time.12 men 1/9 job 1 daydivide the 12 men by 12.1 man 1/108 job in 1 day Now add the 6 new workers.18 men 1/6 job in 1 day Now how long will 18 guys to do 1 job in how many days.18 guys can do it in 6 days.You need 1 more day.......
12 men can complete 5/9 of a job in 5 days. How many more days are required to complete the job if 6 more men are added? The answer is 1 but i can't figure out how to get to that answer.
Math whizzes please help create a step by step procedure on how you solved this problem. So i will know how to problems like this in the future, thanks!

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Break it down one step at a time.

12 men 5/9 job 5 days divide the last two by 5
12 men 1/9 job 1 day divide the 12 men by 12. Do the same to 1/9

1 man 1/9 * 1/12 job in 1 day
1 man 1/108 job in 1 day Now add the 6 new workers.

18 men 18/108 job in 1 day
18 men 1/6 job in 1 day Now how long will 18 guys to do 1 job in how many days.
18 men 1 job in 6 days

12 guys can do it in 5 days
18 guys can do it in 6 days.

You need 1 more day.

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12 men complete 5/9 of a job in 5 days
12 men complete (5/9)/5 of a job in one day
1 man completes (1/9) / 12 of a job in one day

1 man completes 1 / 108 of a job in one day

12 + 6 = 18

x(18/108) = 1 - 5/9
x(1/6) = 4/9
x = 24/9 more days to complete the 4/9 of the job left to do

x = 8/3 more days

not 1
1
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