Someone please tell me how to solve this problem or where i can find out how.

If |2x + 9|= 33, x =

two cases to consider
2x + 9 = 33
2x = 24
x = 12

-(2x+9)= 33 which is the same as
2x+9 = -33
2x = -42
x = -21

With an absolute value problem, you really have two equations. One equation treats the absolute value portion as positive and the other treats the absolute value portion as negative. For this equation, we have:

2x + 9 = 33
- (2x + 9) = 33, or 2x + 9 = -33

Solve for both equations:
2x = 24
x = 12

2x + 9 = -33
2x = -42
x = -21

So your two answers are x = 12 and x = -21.

Since this is an absolute value, you have to make the answer (which, in this case is 33) both positive and negative, such that you'll have two equations:

1) 2x + 9 = 33
2) 2x + 9 = -33

Then you isolate the 'x'

1) 2x = 33 - 9
2x = 24
2) 2x = -33 - 9
2x = -42

Then you divide out the '2' so that the x is by itself ...

1) x = 24/2
x = 12
2) x = -42/2
x = -21

Then you have your set of answers, which is

x = 12 or -21

Remove the bars by writing two equations.
Since 33 and -33 have the same absolute value,

2x+9= 33 or 2x+9= -33

2x= 24. Or 2x= -42

X =12 Or -21

I2x + 9I = 33

2x + 9 = 33

2x = 24

x = 12

or

- (2x + 9) = 33

- 2x - 9 = 33

- 2x = 42

x = - 21

find x values that satisfy one or both of these equations:

2x + 9 = 33

-(2x + 9) = 33

2 x X + 9 = 33 , that's what it says, so if we remove the 9 it becomes this 2x X = 24 , (33-9), 24 : 2 = 12 , X = 12