the radius of a right circular cylinder is increasing at the rate of 6in/sec, while the height is decreasing at the rate of 8in/sec. At what rate is the volume of the cylinder changing when the radius is 13 in and the height is 12 in. ??
thank you
thank you
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V = pi*r^2h
h = 12 in + 6in/sec
r = 13 in - 8 in/sec
V = pi * (12 + 6t)(13 - 8t)^2
V = pi * (12 + 6t)(169 - 208t + 64t^2)
V = pi * (2028 -1482t -480t^2 +384t^3)
V' = -1428 - 960t + 1152t^2
h = 12 in + 6in/sec
r = 13 in - 8 in/sec
V = pi * (12 + 6t)(13 - 8t)^2
V = pi * (12 + 6t)(169 - 208t + 64t^2)
V = pi * (2028 -1482t -480t^2 +384t^3)
V' = -1428 - 960t + 1152t^2