i know it turns into {(15,0), (10,-2), (-5,-8), (-10, -10)} but I'm not sure how to get there... please help!!
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you just need to plug the x values into the equation to find if it is true or not.
For example, (15,0)
x= 15-----> y=2/5(15)-6 = 0 ( the equation is true)
x= 10-----> y=2/5(10)-6 = -2 ( the equation is true)
x= -5-----> y=2/5(-5)-6 = -8 ( the equation is true)
x= -10-----> y=2/5(-10)-6 = -10 ( the equation is true)
then, you simply draw the the line based on the x' and y's that you have.
Good luck
For example, (15,0)
x= 15-----> y=2/5(15)-6 = 0 ( the equation is true)
x= 10-----> y=2/5(10)-6 = -2 ( the equation is true)
x= -5-----> y=2/5(-5)-6 = -8 ( the equation is true)
x= -10-----> y=2/5(-10)-6 = -10 ( the equation is true)
then, you simply draw the the line based on the x' and y's that you have.
Good luck
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To graph it you would start at the y intercept (-6) so graph (0,-6). Then go up 2 lines and over 5 and plot that point and so on..
Or did you mean to actuAlly get the coordinates in equation? You would fill in the x and solve for y. For example if you wanted 5 for the x coordinate substitute 5 as x
Or did you mean to actuAlly get the coordinates in equation? You would fill in the x and solve for y. For example if you wanted 5 for the x coordinate substitute 5 as x
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The equation of the line is y =(2/5)x-6
So plug in x values to find y values. Then each (x ,y) is a point on the line.
The x may be any number.
In your first example, x is 15
Then (2/5)(15)-6
= (2/5)(15/1)-6
=6-6
=0
So (15,0) is a point.
So plug in x values to find y values. Then each (x ,y) is a point on the line.
The x may be any number.
In your first example, x is 15
Then (2/5)(15)-6
= (2/5)(15/1)-6
=6-6
=0
So (15,0) is a point.