Algebra word problem about a cyclist traveling at certain mph
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Algebra word problem about a cyclist traveling at certain mph

[From: ] [author: ] [Date: 11-06-28] [Hit: ]
48=(rate of cyclist-rate of wind)*2.....60=(rate of cyclist+rate of wind)*2.......
A cyclist travels 48km in 2 hours going against the wind. She travels 60km with the wind in the same amount of time. What is the rate of the cyclist in still air and what is the rate of the wind?

*scratching head*

Can someone tell me the appropriate format to use?

-
use Distance=rate*time

48=(rate of cyclist-rate of wind)*2.....24=(rate of cyclist-rate of wind)

60=(rate of cyclist+rate of wind)*2....30=(rate of cyclist+rate of wind)

Let x be rate of cyclist and y be the rate of wind

24=x-y
30=x+y

Linear combination.

54=2x
x=27

24=27-y
y=3

rate of cyclist= 27 km/ hr
rate of wind=3km/hr
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