lim(x→+∞)=(√(x )+1)/(3+x))
Thank you so much.
Thank you so much.
-
lim(x→+∞)=(√(x )+1)/(3+x))
Dividing the numerator and denominator with x
=> limit
= lim(x→+∞)=(1/√(x ) + 1/x)/(3/x + 1))
= 0/1
= 0.
Dividing the numerator and denominator with x
=> limit
= lim(x→+∞)=(1/√(x ) + 1/x)/(3/x + 1))
= 0/1
= 0.
-
The 1/(3+x) is going to zero, since the denominator is increasing without bound, while the numerator is constant. The Square Root of X is going to infinity. So infinity plus 0 is infinity.
Your answer is infinity.
Your answer is infinity.