Help about limits, i don't remember which rule to use in this question
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Help about limits, i don't remember which rule to use in this question

[From: ] [author: ] [Date: 11-05-27] [Hit: ]
-The 1/(3+x) is going to zero, since the denominator is increasing without bound, while the numerator is constant.The Square Root of X is going to infinity.So infinity plus 0 is infinity.Your answer is infinity.......
lim(x→+∞)=(√(x )+1)/(3+x))
Thank you so much.

-
lim(x→+∞)=(√(x )+1)/(3+x))
Dividing the numerator and denominator with x
=> limit
= lim(x→+∞)=(1/√(x ) + 1/x)/(3/x + 1))
= 0/1
= 0.

-
The 1/(3+x) is going to zero, since the denominator is increasing without bound, while the numerator is constant. The Square Root of X is going to infinity. So infinity plus 0 is infinity.

Your answer is infinity.
1
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