Math help!!!!!!!!!!!!!!!!!!!?????? please

Indicate in standard form the equation of the line passing through the given point and having the given slope.

B(6, 2), m = - 1/2

We are going to use the point-slope formula y - y0 = m(x - x0). By plugging in the point B and the slope m, we get
y - 2 = -1/2(x - 6) implies y = (-1/2)x + 5 by solving for y. The standard form would be y + (1/2)x - 5 = 0

So the general equation is y = mx + b

m = -1/2 so you can sub that in, as well as x = 6 and y = 2

So now the equation is 2 = -1/2(6) + b and you just need to solve for b

2 = -1/2(6) + b
2 = -3 + b
5 = b

So the equation is y = -1/2x + 5
Hope that helps !

standard form with point (a,b) and slope m is y-b =m(x-a)

so for your question, equation is y-2= (-1/2)(x-6)

2y-4=6-x
2y+x=10

or x+2y=10
all the best.

well y=mx+b
so 2=-1/2(6)+b
and then solve for b

y=mx+b

2=(-1/2)(6)+b
2=(-3)+b
5=b

y=(-1/2)x+5